Math

I need help with this problem:

Two planes start from Los Angeles International Airport and fly in opposite directions. The second plane starts ½ hour after the first plane, but its speed is 80 kilometers per hour faster. Find the airspeed of each plane if 2 hours after the first plane departs the planes are 3200 kilometers apart.

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asked by Kelsey
  1. distance slow plane=vt
    distance fast plane=.5*(v+80)t +(v+80)t

    3200=sum of the two distances, or
    3200=v*2+.t(v+80)*2 + (v+80)*2
    solve for v, then for the faster plane, its speed is v+80

  2. Whats 1/5 (one fifth) of 200?

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    posted by Marney
  3. 40 times five is 200

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