A 15.7 kg block is at rest on a ramp, whose angle is 12.1 degrees from the horizontal.

How much Normal Force is acting on the block?

m*g = 15.7 * 9.8 = 153.9 N. = Wt. of

block.

Fn = 153.9*cos12.1 = 150.4 N.

To find the normal force acting on the block, we need to understand the forces acting on it.

In this case, the block is on a ramp inclined at an angle of 12.1 degrees from the horizontal. The forces acting on the block are the weight of the block (mg) acting vertically downward and the normal force (N) acting perpendicular to the ramp's surface.

The weight of the block can be calculated using the formula:
Weight (W) = mass (m) × acceleration due to gravity (g)

Given:
Mass of the block (m) = 15.7 kg
Acceleration due to gravity (g) ≈ 9.8 m/s²

Substituting the values, we have:
W = 15.7 kg × 9.8 m/s²

Now we need to consider the vertical component of the weight due to the inclined ramp. This can be found by multiplying the weight by the sine of the angle of the ramp.

Vertical component of weight = W × sin(θ)

Where θ = 12.1 degrees

Now we can find the normal force by subtracting the vertical component of weight from the weight of the block.

Normal force (N) = W - Vertical component of weight

Let's calculate it:
Weight (W) = 15.7 kg × 9.8 m/s²
Vertical component of weight = W × sin(θ)
Normal force (N) = W - Vertical component of weight

After plugging in the values and performing the calculations, you will be able to find the value of the normal force acting on the block.