How many grams of a 17.7% potassium sulfate solution would contain 419.9 g potassium sulfate? Answer in units of g

To determine the number of grams of a 17.7% potassium sulfate solution that would contain 419.9 g of potassium sulfate, we need to use the concentration and the given weight of the potassium sulfate.

The concentration of a solution is expressed as a percentage. In this case, the solution is 17.7% potassium sulfate. This means that in every 100 mL of the solution, there are 17.7 grams of potassium sulfate.

To find the number of grams of potassium sulfate in the solution that would contain 419.9 g of potassium sulfate, we can set up a proportion:

(17.7 g / 100 mL) = (419.9 g / x mL)

Since the g/mL units cancel out, we can solve for x by cross-multiplication:

17.7 g * x mL = 100 mL * 419.9 g

Now we can solve for x:

x = (100 mL * 419.9 g) / 17.7 g

x ≈ 2379.66 mL

Since we want to express the answer in grams, we need to convert the volume from milliliters to grams. We can do this by utilizing the fact that 1 mL of water is approximately equal to 1 g. Hence, 2379.66 mL is approximately equal to 2379.66 g.

Therefore, approximately 2379.66 grams of a 17.7% potassium sulfate solution would contain 419.9 g of potassium sulfate.