Write the equation for the dissolution of
NH4NO3 in water. If 5.95 mol of NH4NO3
are dissolved, how many total moles of ions
are produced?
Answer in units of mol
.0096
The equation for the dissolution of NH4NO3 in water is:
NH4NO3(s) → NH4+(aq) + NO3-(aq)
When NH4NO3 dissolves in water, it breaks apart into its constituent ions: NH4+ and NO3-. We need to find the total moles of ions produced when 5.95 mol of NH4NO3 are dissolved.
From the balanced equation, we can see that 1 mole of NH4NO3 produces 1 mole of NH4+ ions and 1 mole of NO3- ions. Therefore, for every mole of NH4NO3 dissolved, we get 1 mole of each ion.
Since we have 5.95 mol of NH4NO3, we will also have 5.95 mol of NH4+ ions and 5.95 mol of NO3- ions.
Therefore, the total moles of ions produced when 5.95 mol of NH4NO3 are dissolved is 5.95 mol.