A jar contains 21 brown, 4 violet, and 6 white marbles. A marble is drawn at random. what is the probability you will not draw a white marble?
Answer 6/31
A jar contains 6 pink, 7 violet, 26 green, and 13 blue marbles. A marble is drawn at random. what is the probability you will draw a violet, pink, or blue marble?
Answer 7/39, pink = 6/39, blue = 13/39
ummm, 6+7+26+13 = ?
So then number 1 is correct
Number 2 is Violet - 7/52 Pink - 6/32
Blue - 13/52
now you're cookin' (aside from that pesky 32!)
To find the probability of certain events, you need to know the total number of possible outcomes and the number of favorable outcomes.
In the first scenario:
- The total number of marbles in the jar is 21 (brown) + 4 (violet) + 6 (white) = 31.
- We want to find the probability of not drawing a white marble, which means getting either a brown or violet marble.
- The favorable outcomes are the number of brown and violet marbles, which is 21 + 4 = 25.
- Therefore, the probability of not drawing a white marble is 25/31.
In the second scenario:
- The total number of marbles in the jar is 6 (pink) + 7 (violet) + 26 (green) + 13 (blue) = 52.
- We want to find the probability of drawing a violet, pink, or blue marble.
- The favorable outcomes are the number of violet, pink, and blue marbles, which is 7 + 6 + 13 = 26.
- Therefore, the probability of drawing a violet, pink, or blue marble is 26/52, which simplifies to 1/2 or 13/26.
If you want to find the individual probabilities for each marble color:
- The probability of drawing a pink marble is 6/52, which simplifies to 3/26.
- The probability of drawing a blue marble is 13/52, which simplifies to 1/4 or 13/52.
Remember that the probabilities must add up to 1 since one of the outcomes is guaranteed.