If I had 32 kilobytes and was converting them to Hectobytes using the K H D b d c m would it be 320 hectobytes?

1 answer

yes

Similar Questions

Omar downloaded emojis. Each emoji had a file size of 3.7 kilobytes. What is the total file size in kilobytes of 6 of these

Top answer: The total file size in kilobytes of 6 emojis is 6 * 3.7 = 22.2 kilobytes. So the correct answer is Read more.
When converting measures, which is a true statement?If you are converting to a smaller unit, you should subtract. If you are

Top answer: If you are converting to a smaller unit, you should multiply. Read more.
Omar downloaded emojis. Each emoji had a file size of 3.7 kilobytes. What is the total file size in kilobytes of 6 of these

Top answer: The total file size of 6 emojis is (6 emojis * 3.7 kilobytes/emoji) = <<6*3.7=22.2>>22.2 kilobytes. Read more.
this is a multiple choiceWhat is 10000000000 Bytes based on engineering notation? a) 1 TeraBytes b) 10 TeraBytes c) 10 GigaBytes

Top answer: I think my answer is c) Read more.
if about 32,680 kilobytes of memory is still available how many more pictures can they take

Top answer: 42 Read more.
1,680 kilobytes in 4 minutes how do i solve this

Top answer: Rate = 1680kb/4min = 420kb/1min = 420kb/60s = 7 kb/s. Read more.
Converting Between Systems PortfolioUse what you have learned about converting between metric and imperial measurements to

Top answer: To determine if Roger can use the 8-liter bowl to mix all the ingredients for the punch, we need to Read more.
Converting Between Systems PortfolioUse what you have learned about converting between metric and imperial measurements to

Top answer: To determine if Roger can use the 8-liter bowl to mix all the ingredients for the punch, we need to Read more.
1,680 kilobytes in 4 minutes..........how do u get it....... lesson 6-2 ......rates....6th grade pg. 289 ......#2

Top answer: 1680/4 = ? Read more.
Which hard drive would store the most information?4 gigabytes 4 kilobytes 2 terabytes 6 nanobytes

Top answer: 2 terabytes Read more.