Calculate the H3O+ concentration present in water under the following conditions. Enter your answer in scientific notation.
[OH-] = 2.8 x 10-7 M
[OH-] = 8.8 x 10-3 M
[OH-] = 2.4 x 10-11 M
See your posts above.
To calculate the H3O+ concentration given the OH- concentration, you will need to use the equation for the ion product of water (Kw = [H3O+][OH-] = 1.0 x 10^-14 at 25 degrees Celsius).
Let's go through each condition step by step:
1. [OH-] = 2.8 x 10^-7 M:
Since Kw = [H3O+][OH-], and Kw is a constant, we can rearrange the equation to solve for [H3O+]. Divide both sides by [OH-]:
Kw / [OH-] = [H3O+]
(1.0 x 10^-14) / (2.8 x 10^-7) = [H3O+]
[H3O+] = 3.57 x 10^-8 M
Therefore, the H3O+ concentration is 3.57 x 10^-8 M.
2. [OH-] = 8.8 x 10^-3 M:
Using the same equation, divide Kw by [OH-]:
Kw / [OH-] = [H3O+]
(1.0 x 10^-14) / (8.8 x 10^-3) = [H3O+]
[H3O+] = 1.14 x 10^-12 M
Thus, the H3O+ concentration is 1.14 x 10^-12 M.
3. [OH-] = 2.4 x 10^-11 M:
Apply the equation once again:
Kw / [OH-] = [H3O+]
(1.0 x 10^-14) / (2.4 x 10^-11) = [H3O+]
[H3O+] = 4.17 x 10^-4 M
Therefore, the H3O+ concentration is 4.17 x 10^-4 M.
In summary, the H3O+ concentration under each condition is:
1. [OH-] = 2.8 x 10^-7 M: 3.57 x 10^-8 M
2. [OH-] = 8.8 x 10^-3 M: 1.14 x 10^-12 M
3. [OH-] = 2.4 x 10^-11 M: 4.17 x 10^-4 M.