_12 + 4n = 6(n-2)
12 + 4n = 6(n - 2)
12 + 4n = 6n - 12
+12 +12
24 + 4n = 6n
- 4n -4n
24 = 2n
solve for n and you've got your answer!
n=12
To solve the given equation _12 + 4n = 6(n-2), we will follow these steps:
Step 1: Distribute the 6 on the right side of the equation by multiplying it with both terms inside the parentheses.
This gives us: _12 + 4n = 6n - 12
Step 2: Remove the parentheses by combining like terms on the right side of the equation.
This gives us: _12 + 4n = 6n - 12
_12 + 4n = 6n - 12
Step 3: Move all the terms containing the variable "n" to one side of the equation by adding or subtracting.
We can move the 4n term to the right side by subtracting 4n from both sides of the equation.
This gives us: _12 + 4n - 4n = 6n - 12 - 4n
_12 = 2n - 12
Step 4: Continue simplifying the equation by adding or subtracting like terms.
We can add 12 to both sides of the equation to isolate the term containing "n" on one side.
This gives us: _12 + 12 = 2n - 12 + 12
0 = 2n
Step 5: Solve for "n" by dividing both sides of the equation by the coefficient of "n" (which is 2).
This gives us: 0/2 = 2n/2
0 = n
Therefore, the solution to the equation _12 + 4n = 6(n-2) is n = 0.