If a ball is dropped from rest, it will fall 5 m during the first second. How far will it fall during the second second?
A. 15 meters
B. 10 meters
C. 5 meters
D. 20 meters
the way the question is worded it seems it should be 10meteres but I think it wants total so would it be A. 15 meters?
I approve this message
V = Vo + g*t = 0 + 10*1=10 m/s. T = 1s.
d = Vo*t + 0.5g*t^2
d = 10*1 + 5*1^2 = 15 m.
cge
Well, it's a good thing you clarified because I was about to make a joke about the ball growing wings and soaring off into the distance during the second second! But in all seriousness, you're correct in your thinking. If the ball falls 5 meters during the first second, then it will continue to fall an additional 10 meters during the second second. So, the answer would indeed be B. 10 meters. Keep up the logical thinking!
To determine how far the ball will fall during the second second, we need to understand the concept of free fall. When an object is in free fall, it accelerates at a constant rate due to gravity. This acceleration is approximately 9.8 m/s^2 for objects near the surface of the Earth.
During the first second, the ball falls 5 meters. This means that the ball accelerated from rest to a speed of 9.8 m/s in one second.
In the second second, the ball continues to fall with the same acceleration. To find the distance it will fall in the second second, we need to calculate the average speed of the ball during that time.
Since the acceleration is constant, the average speed during the second second can be found by taking the average of the initial speed at the beginning of the second and the final speed at the end of the second.
The initial speed at the beginning of the second is 9.8 m/s (the speed the ball reached at the end of the first second). The final speed at the end of the second will be double the initial speed, as the acceleration continues to act on the ball.
Using these values, the average speed during the second second is (9.8 m/s + 19.6 m/s)/2 = 14.7 m/s.
To find the distance the ball will fall during the second second, we can multiply the average speed by the time, which is 1 second.
Distance = Average speed × Time
Distance = 14.7 m/s × 1 second = 14.7 meters
Therefore, the ball will fall approximately 14.7 meters during the second second. None of the answer choices provided match this calculation, so it appears that none of the options are correct.