When an F14 fighter jet takes off, its wings are 110 degrees from the line of flight. To reach its maximum speed, the wings pull to a back position that cretes an angle from the line of flight that is 22 degrees less than a straight angle. Moving at 0.5 degrees per second, how long will it take the wings to move from their takeoff position to a maximum speed position?
158-110 = 48 degrees
so, it will take 96 seconds
To calculate how long it will take for the F14 fighter jet wings to move from their takeoff position to a maximum speed position, we need to find the difference in angles and divide it by the rate of movement.
Given information:
- The wings start at an angle of 110 degrees from the line of flight.
- The maximum speed position angle is 22 degrees less than a straight angle (which is 180 degrees).
- The wings move at a rate of 0.5 degrees per second.
To find the difference in angles, we subtract the maximum speed position angle from the takeoff position angle:
Difference in angles = 180 degrees - (180 degrees - 22 degrees)
= 180 degrees - 158 degrees
= 22 degrees
Now, we can calculate the time it will take for the wings to move this difference in angles using the rate of movement:
Time = Difference in angles / Rate of movement
= 22 degrees / 0.5 degrees per second
= 44 seconds
Therefore, it will take the wings 44 seconds to move from their takeoff position to the maximum speed position.