I'm confused. Can you help?
"The community pool charges $8.00 for adults and $5.00 for children. The total revenue for a
particular cloudy day is $648.00. Determine the number of adults and the number of children who
went to the pool that day if twice as many children paid for admission as adults."
if there were a adults, there were 2a children, so
8*a + 5*2a = 648
18a = 648
a = 36
36 adults and 72 children
Of course, I'll be happy to help you with that problem!
Let's start by assigning variables to the unknowns in the problem. Let's say:
- A represents the number of adults
- C represents the number of children
According to the problem, we know that the community pool charges $8.00 for adults and $5.00 for children, and the total revenue for that particular cloudy day is $648.00.
To find the number of adults and children who went to the pool that day, we need to set up a system of equations based on the given information.
Equation 1: The total amount paid by adults + the total amount paid by children = $648.00.
The total amount paid by adults is 8A, and the total amount paid by children is 5C. So, our equation becomes:
8A + 5C = 648
Equation 2: "Twice as many children paid for admission as adults."
Since there are twice as many children as adults, the number of children (C) is equal to 2 times the number of adults (A). In equation form:
C = 2A
Now we have two equations:
8A + 5C = 648 (Equation 1)
C = 2A (Equation 2)
To solve the system of equations, we can use substitution or elimination method. Let's use substitution:
Substituting Equation 2 into Equation 1:
8A + 5(2A) = 648
8A + 10A = 648
18A = 648
A = 648/18
A = 36
So, the number of adults who went to the pool that day is 36.
Now we can use this value to find the number of children:
C = 2A
C = 2(36)
C = 72
Therefore, the number of children who went to the pool that day is 72.
So, the final answer is that there were 36 adults and 72 children who went to the pool on that particular cloudy day.