How many moles of sulfur are present in 2.6 moles of Al2(SO4)3?
2.5 mol Al2(SO4) x [3 mol S/1 mol Al2(SO4)3]= ?
To determine the number of moles of sulfur in 2.6 moles of Al2(SO4)3, we first need to understand the chemical formula of Al2(SO4)3.
Al2(SO4)3 indicates that there are two aluminum atoms (Al) and three sulfate groups (SO4). Each sulfate group consists of one sulfur atom (S) and four oxygen atoms (O).
Therefore, we can calculate the number of moles of sulfur by multiplying the number of moles of Al2(SO4)3 by the ratio of sulfur atoms to Al2(SO4)3.
The molecular formula of Al2(SO4)3 tells us that for every 1 mol of Al2(SO4)3, we have 3 moles of sulfur atoms.
So, to find the moles of sulfur in 2.6 moles of Al2(SO4)3, we will use the following calculation:
moles of sulfur = moles of Al2(SO4)3 * (3 moles of S / 1 mole of Al2(SO4)3)
Substituting the values, we have:
moles of sulfur = 2.6 moles * (3 moles / 1 mole)
After performing the calculation, we find that there are 7.8 moles of sulfur in 2.6 moles of Al2(SO4)3.