How would you precipitate BaCrO4 from a solution of Ba(NO3)2 and K2CrO7?
To precipitate BaCrO4 from a solution of Ba(NO3)2 and K2CrO7, you need to follow a few steps:
1. Write the balanced chemical equation: Ba(NO3)2 + K2CrO7 → BaCrO4 + 2KNO3
2. Divide the equation into ionic compounds: Ba2+ + 2NO3^- + 2K+ + CrO4^2- → BaCrO4 + 2K+ + 2NO3^-
3. Identify the precipitate: In this case, BaCrO4 is the desired precipitate.
4. Determine the correct reactant ratios: According to the equation, the stoichiometric ratio of Ba(NO3)2 to K2CrO7 is 1:1.
5. Add the reagents in the correct proportions: Mix the solutions of Ba(NO3)2 and K2CrO7 in a 1:1 molar ratio. For example, if you have 100 mL of 0.1 M Ba(NO3)2, you would need to mix it with 100 mL of 0.1 M K2CrO7.
6. Observe the precipitation: As you mix the solutions, you'll notice the formation of a yellow solid, which is the BaCrO4 precipitate. Be sure to perform this step in a controlled environment, like a fume hood, due to the potential toxicity of chromium compounds.
7. Recover the precipitate: The BaCrO4 precipitate can be separated from the solution by filtration. Use a filter paper or a filter funnel to collect the solid while allowing the liquid to pass through.
8. Wash and dry the precipitate: Rinse the precipitate with distilled water to remove any impurities, and then transfer it to a drying dish. Allow it to air dry or use an oven set to a low temperature, if necessary.
By following these steps, you should be able to precipitate BaCrO4 from a solution of Ba(NO3)2 and K2CrO7.