7.00 grams of sugar (C12H22O11) are dissolved

in water to make 1 L of solution. What is the
concentration of this solution?
Answer in units of M

mols solute = grams/molar mass

Then M = mols/L solution.

Thanks!

To find the concentration of a solution, we need to calculate the molarity (M).

Molarity is defined as the number of moles of solute per liter of solution. In order to calculate the molarity, we first need to determine the number of moles of sugar (C12H22O11) in the solution.

To find the number of moles, we can use the formula:

moles = mass (in grams) / molar mass (in grams per mole)

The molar mass of sugar (C12H22O11) can be calculated by summing the atomic masses of carbon (C), hydrogen (H), and oxygen (O) in one molecule of sugar.

C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol

Using these atomic masses, we can calculate the molar mass of sugar:

Molar mass (C12H22O11) = (12 * 12.01 g/mol) + (22 * 1.01 g/mol) + (11 * 16.00 g/mol)

Now we can plug in the values into the formula to find the moles of sugar:

moles = 7.00 g / molar mass (C12H22O11)

Next, we need to calculate the volume of the solution. In this case, we are given that the volume is 1 L.

Now we can calculate the concentration (molarity):

Molarity (M) = moles / volume (in liters)

Substituting the values we found earlier:

Molarity (M) = moles / 1 L

Thus, we have calculated the concentration of the sugar solution in units of Molarity (M).