L=length
w=width
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eqn 1 is 2L + 2w = 28
eqn 2 is w= (1/2)L+2
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solve for L and w.
Post your work if you get stuck.
http://www.jiskha.com/display.cgi?id=1169164168
Posted by Ashley on Thursday, January 18, 2007 at 6:49pm.
John made a rectangular pen for his dog using 28 feet of fencing.If the width of the pen is 2 feet more than one-half the length,what are the length and width of the pen?
2L + 2w=28
W= L/2+ 2
2L + 2(L/2 + 2)=28
solve.
To solve the equations, we'll start with equation 2 and substitute it into equation 1.
First, let's simplify equation 2:
w = L/2 + 2
Next, substitute this expression for w in equation 1:
2L + 2(L/2 + 2) = 28
Now, simplify and solve for L:
2L + L + 4 = 28
3L + 4 = 28
3L = 24
L = 8
Now that we have found the value of L, we can substitute it back into equation 2 to find w:
w = L/2 + 2
w = 8/2 + 2
w = 4 + 2
w = 6
Therefore, the length (L) of the pen is 8 feet and the width (w) is 6 feet.