I have 8 marbles: 3 blue, 1 green, 4v reds. What is the probability of selecting a blue marble twice with replacement and twice without replacement

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

3/8 * 3/8 = ?

3/8 * (3-1)/(8-1) = ?