an airplane takes off at an angle of 30 to the horizontal. if the component of its velocity along the horizontal is 250 km/h , what is its actual velocity? also find the vertical component.

No

To find the actual velocity and vertical component of the airplane, we can use trigonometry. We can use the given angle and the horizontal component of the velocity to determine the remaining components.

First, let's label the components of the velocity:

Horizontal component (Vx) = 250 km/h
Vertical component (Vy) = ?

To find the actual velocity (V), we can use the Pythagorean theorem:

V^2 = Vx^2 + Vy^2

Now, substitute the given values:

V^2 = (250 km/h)^2 + Vy^2

To solve for V, we need to calculate the square root of both sides of the equation:

V = √[(250 km/h)^2 + Vy^2]

To find the vertical component (Vy), we can use the given angle (30 degrees) and the horizontal component (Vx):

Vy = Vx * tan(angle)

Substitute the values:

Vy = (250 km/h) * tan(30°)

Now, calculate the values using a calculator:

Vy = (250 km/h) * tan(30°)
≈ (250 km/h) * 0.577 (approximating the tan(30°) to 0.577)
≈ 144.25 km/h

Finally, substitute the vertical component value into the equation for the actual velocity:

V = √[(250 km/h)^2 + (144.25 km/h)^2]
≈ √[62500 km^2 /h^2 + 20844.06 km^2 /h^2]
≈ √[83344.06 km^2 /h^2]
≈ 288.6 km/h

Therefore, the airplane's actual velocity is approximately 288.6 km/h, and its vertical component is approximately 144.25 km/h.

Xo = 250 km/h

A = 30o

Vo = Xo/cosA = 250/cos30 = 288.7 km/h.

Yo = Vo*sin30 = 288.7*sin30 = 144.3 km/h

A car moving with the velocity of 20m/s at 30 to the horizontal, what is the components of the velocity along the horizontal