pre-calculus

Find the real and imaginary zeros for the following polynomial function.
T(b)= 147b^3-35b^2-19b+3

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  1. 147b^3-35b^2-19b+3 = 0

    Since 147 = 7*7*3, I'd try using those coefficients first, since the inside coefficients are relatively small. A little playing around shows that

    T(b) = (7b-1)(7b-3)(3b+1)

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    posted by Steve

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