Two motorcycles travel toward each other from cities that are about 320km apart at rates of 95km/hr and 65km/hr. They started at the same time . In how many hours will they meet?
distance covered by faster driver --- x km
distance covered by slower driver --- 320-x km
The must have driven the same abount of time, so
x/95 = (320 - x)/65
65x = 30400 - 95x
160x = 30400
x = 190
time = 190/95 = 2 hrs
check:
time of faster driver = 190/95 = 2
time of slower driver = (320-190)/65 = 2
YEAHH
To find out in how many hours the two motorcycles will meet, we can use the formula for calculating the time it takes for two moving objects to meet:
Time = Distance / Relative Speed
First, let's find the relative speed between the two motorcycles:
Relative Speed = Speed of Motorcycle 1 + Speed of Motorcycle 2
Relative Speed = 95 km/hr + 65 km/hr
Relative Speed = 160 km/hr
Now, we can calculate the time it takes for the two motorcycles to meet:
Time = Distance / Relative Speed
Distance = 320 km
Time = 320 km / 160 km/hr
Time = 2 hours
Therefore, the two motorcycles will meet in 2 hours.
To find out in how many hours the motorcycles will meet, we can calculate the time it takes for them to cover the total distance between them.
Let's assume that the motorcycles meet after time 't' hours.
The formula to calculate the distance (D) is given by the formula:
Distance = Speed x Time
For the first motorcycle traveling at 95 km/hr, the distance covered will be (95 km/hr) x (t hours) = 95t km.
Similarly, for the second motorcycle traveling at 65 km/hr, the distance covered will be (65 km/hr) x (t hours) = 65t km.
Since the total distance between the cities is 320 km, the sum of the distances covered by the two motorcycles will be equal to the total distance:
95t + 65t = 320
Simplifying the equation, we get:
160t = 320
Dividing both sides of the equation by 160:
t = 320 / 160
t = 2
Therefore, the motorcycles will meet in 2 hours.