# vapor pressure

The total pressure in a flask containing air and ethanol at 25.7C is 878 mm Hg. The pressure of the air in the flask at 25.7C is 762 mm Hg. If the flask is immersed in a water bath at 450C, the total pressure is 980 mm Hg. The vapor pressure of ethanol at the new temperature is ? mm Hg.
Hint: you will need to correct the pressure of air at the new temperature using the Gas Law: P1/T1 = P2/T2

The air partial pressure increases from 762 mm Hg to (762 mm Hg) x (T2/T1)
=(762)[(273.2+450)/(273.2+25.7)= 1844 mm Hg. This is lower than the new total pressure you listed, which cannot happen. Are you sure you copied all the numbers in the problem correctly?

it's actually 45.0 C. where did u get 273.2? i replaced 450 in the equation u used, and i got 811. but that isnt correct...

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