Factor:
24x^3-3 I think you use the perfect cube formula which would be a^3+b^3=(a-b)(a2+ab+b2)
but not sure how to go about doing this.
24 x^3 - 3
3 (8x^3 - 1)
now 8 x^3 = (2x)^3 perfect cube
and 1 = (1)^3 perfect cube
and
a^3 – b^3 = (a – b)(a^2 + ab + b^2)
note a^3-b^3 not +