phy

Boy throws a penny into a wishing well at a velocity of 2 m/s and at an angle of 45 degrees below horizontal. If the penny takes 1.3 seconds to hit the water, how deep is the well?

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  1. Vo = 2m/s[-45o]
    Xo=2*cos(-45)=1.414 m/s=Hor. component.
    Yo=2*sin(-45)=-1.414 m/s=Ver. component.

    Depth = Yo*t + 0.5g*t^2 =
    -1.414*1.3 + 4.9*1.3^2 = 6.44 m.

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    posted by Henry

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