Iron ores have different amounts of iron per kilogram of ore.
Calculate the mass percent composition of iron for each iron ore: Fe2O3{\rm Fe_2O_3} (hematite), Fe3O4{\rm Fe_3O_4} (magnetite), FeCO3{\rm FeCO_3} (siderite).
For Fe2O3.
(2*atomic mass Fe/molar mass Fe2O3)*100 = ?
The others are done the same way.
To calculate the mass percent composition of iron for each iron ore, we need to determine the mass of iron in each compound and divide it by the total mass of the compound, then multiply by 100.
1. For Fe2O3 (hematite):
The molar mass of Fe2O3 is calculated as follows:
(2 x atomic mass of Fe) + (3 x atomic mass of O) = (2 x 55.845 g/mol) + (3 x 16.00 g/mol) = 159.69 g/mol
The molar mass of Fe in the compound is:
(2 x atomic mass of Fe) = (2 x 55.845 g/mol) = 111.69 g/mol
The mass percent composition of iron in Fe2O3 is:
(111.69 g/mol / 159.69 g/mol) x 100% = 69.93%
Therefore, the mass percent composition of iron in Fe2O3 (hematite) is approximately 69.93%.
2. For Fe3O4 (magnetite):
The molar mass of Fe3O4 is calculated as follows:
(3 x atomic mass of Fe) + (4 x atomic mass of O) = (3 x 55.845 g/mol) + (4 x 16.00 g/mol) = 231.53 g/mol
The molar mass of Fe in the compound is:
(3 x atomic mass of Fe) = (3 x 55.845 g/mol) = 167.54 g/mol
The mass percent composition of iron in Fe3O4 is:
(167.54 g/mol / 231.53 g/mol) x 100% = 72.38%
Therefore, the mass percent composition of iron in Fe3O4 (magnetite) is approximately 72.38%.
3. For FeCO3 (siderite):
The molar mass of FeCO3 is calculated as follows:
atomic mass of Fe + atomic mass of C + (3 x atomic mass of O) = 55.845 g/mol + 12.01 g/mol + (3 x 16.00 g/mol) = 115.85 g/mol
The molar mass of Fe in the compound is simply the atomic mass of Fe, which is 55.845 g/mol.
The mass percent composition of iron in FeCO3 is:
(55.845 g/mol / 115.85 g/mol) x 100% = 48.14%
Therefore, the mass percent composition of iron in FeCO3 (siderite) is approximately 48.14%.
To calculate the mass percent composition of iron for each iron ore, we need to determine the mass of iron in each compound and divide it by the total mass of the compound.
1. Hematite (Fe2O3):
The molecular mass of Fe2O3 is calculated as follows:
(2 x atomic mass of Fe) + (3 x atomic mass of O) = (2 x 55.845) + (3 x 16.00) = 111.69 + 48.00 = 159.69 g/mol
To calculate the mass percent composition of iron in hematite, we need to find the mass of iron and divide it by the total mass of the compound.
Mass of iron in hematite = (2 x atomic mass of Fe) = (2 x 55.845) = 111.69 g/mol
Mass percent of iron = (Mass of iron / Total mass of compound) x 100
= (111.69 / 159.69) x 100
≈ 69.93%
Therefore, the mass percent composition of iron in hematite is approximately 69.93%.
2. Magnetite (Fe3O4):
The molecular mass of Fe3O4 is calculated as follows:
(3 x atomic mass of Fe) + (4 x atomic mass of O) = (3 x 55.845) + (4 x 16.00) = 167.535 + 64.00 = 231.535 g/mol
To calculate the mass percent composition of iron in magnetite, we need to find the mass of iron and divide it by the total mass of the compound.
Mass of iron in magnetite = (3 x atomic mass of Fe) = (3 x 55.845) = 167.535 g/mol
Mass percent of iron = (Mass of iron / Total mass of compound) x 100
= (167.535 / 231.535) x 100
≈ 72.36%
Therefore, the mass percent composition of iron in magnetite is approximately 72.36%.
3. Siderite (FeCO3):
The molecular mass of FeCO3 is calculated as follows:
(1 x atomic mass of Fe) + (1 x atomic mass of C) + (3 x atomic mass of O) = (1 x 55.845) + (1 x 12.011) + (3 x 16.00) = 55.845 + 12.011 + 48.00 = 115.856 g/mol
To calculate the mass percent composition of iron in siderite, we need to find the mass of iron and divide it by the total mass of the compound.
Mass of iron in siderite = (1 x atomic mass of Fe) = (1 x 55.845) = 55.845 g/mol
Mass percent of iron = (Mass of iron / Total mass of compound) x 100
= (55.845 / 115.856) x 100
≈ 48.22%
Therefore, the mass percent composition of iron in siderite is approximately 48.22%.
In summary:
- Hematite (Fe2O3) has a mass percent composition of iron of approximately 69.93%.
- Magnetite (Fe3O4) has a mass percent composition of iron of approximately 72.36%.
- Siderite (FeCO3) has a mass percent composition of iron of approximately 48.22%.