Suppose that 14.9 mL of 0.0512 M NaOH were required to titrate a sample of unknown acid. How many moles of NaOH were used?
mols = M x L = ?
0.76288
To calculate the number of moles of NaOH used in the given titration, we need to use the equation:
moles = concentration × volume
Given information:
Concentration of NaOH solution (c) = 0.0512 M
Volume of NaOH solution used (V) = 14.9 mL
First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).
1 L = 1000 mL
So, V (in L) = 14.9 mL / 1000 mL/L = 0.0149 L
Now we can calculate the moles of NaOH used:
moles = 0.0512 M × 0.0149 L
Simply multiply the concentration (in moles per liter) by the volume (in liters) to get the moles of NaOH used:
moles = 0.0512 × 0.0149 = 0.00076288 moles
Therefore, approximately 0.00076288 moles of NaOH were used in the titration.