Calculate the mass of nickel(II) sulfate and the mass of water contained in 200. g of a 6.00% solution of nickel(II) sulfate
6% (is that w/w ?) means 6g NiSO4 in 100 g solution. That is 6g NiSO4/(6g NiSO4 + 94 g H2O).
So 200 g sample would contain twice those amounts.
To calculate the mass of nickel(II) sulfate and the mass of water in the solution, we need to multiply the mass of the solution by the percentage of nickel(II) sulfate.
Step 1: Calculate the mass of nickel(II) sulfate.
Mass of nickel(II) sulfate = Mass of solution * Percentage of nickel(II) sulfate
Mass of nickel(II) sulfate = 200 g * 6.00% = 200 g * 0.060
Mass of nickel(II) sulfate = 12.00 g
Step 2: Calculate the mass of water.
Mass of water = Mass of solution - Mass of nickel(II) sulfate
Mass of water = 200 g - 12.00 g = 188.00 g
Therefore, the mass of nickel(II) sulfate in the solution is 12.00 g, and the mass of water is 188.00 g.
To calculate the mass of nickel(II) sulfate and the mass of water in a 6.00% solution of nickel(II) sulfate, you first need to determine the amount of nickel(II) sulfate and water present in the solution.
Step 1: Convert the percentage concentration to a decimal.
The given solution has a concentration of 6.00%, which means there are 6.00 grams of nickel(II) sulfate for every 100 grams of solution. To convert this to a decimal, divide 6.00 by 100:
6.00% = 6.00 / 100 = 0.06
Step 2: Calculate the mass of nickel(II) sulfate.
Multiply the percentage concentration (0.06) by the total mass of the solution (200 g):
Mass of nickel(II) sulfate = 0.06 × 200 g = 12 g
So, there are 12 grams of nickel(II) sulfate in the 200 g solution.
Step 3: Calculate the mass of water.
To determine the mass of water, subtract the mass of nickel(II) sulfate from the total mass of the solution:
Mass of water = Total mass of solution - Mass of nickel(II) sulfate
Mass of water = 200 g - 12 g = 188 g
Therefore, there are 188 grams of water in the 200 g solution.