if 25.0 mL of 15M nitric acid is diluted to 125 mL, what is the concentration of the new solution?
i got 3M but i don't think its right
15M x (25.0 mL/125 mL) = ?
Or you're diluting it by a factor of 5 and 15/5 = ?
To find the concentration of the new solution after dilution, you can use the formula:
C1V1 = C2V2
Where:
C1 is the initial concentration of the solution (15 M)
V1 is the initial volume of the solution (25.0 mL)
C2 is the final concentration of the solution (unknown)
V2 is the final volume of the solution (125 mL)
Now let's plug in the values we have:
(15 M)(25.0 mL) = C2(125 mL)
375 M mL = 125 C2
To solve for C2, we can divide both sides of the equation by 125 mL:
375 M mL / 125 mL = C2
C2 = 3 M
So, the concentration of the new solution after dilution is indeed 3 M. Your answer is correct!