if 25.0 mL of 15M nitric acid is diluted to 125 mL, what is the concentration of the new solution?
i got 3M but i don't think its right
To find the concentration of the new solution, we can use the formula:
C1 × V1 = C2 × V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution (what we're trying to find)
V2 = final volume of the solution
Given:
C1 = 15 M (initial concentration of nitric acid)
V1 = 25.0 mL (initial volume of the nitric acid)
V2 = 125 mL (final volume after dilution)
Now, let's plug the values into the formula:
15 M × 25.0 mL = C2 × 125 mL
To solve for C2 (final concentration), divide both sides of the equation by 125 mL:
C2 = (15 M × 25.0 mL) / 125 mL
C2 = (375.0 mol/L·mL) / 125 mL
C2 = 3 M
So, your initial calculation of 3 M is indeed correct. The final concentration of the solution after dilution is 3 M.