Calculate the molarity of a bleach solution that is 8% by mass (m/v) or 8g/100mL sodium

hypochlorite.

To calculate the molarity of a bleach solution, we need to know the mass of sodium hypochlorite (NaClO) in the solution and the volume of the solution.

Given that the bleach solution is 8% by mass, this means that there are 8 grams of sodium hypochlorite in every 100 mL of solution.

First, we need to convert the given percentage mass to grams.

To do this, we calculate:
Mass of NaClO = (8% / 100) x 100 mL = 8 grams

Next, we need to calculate the molarity using the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

To calculate moles of solute, we divide the mass of NaClO by its molar mass.

The molar mass of NaClO can be calculated as:
Na (sodium) + Cl (chlorine) + O (oxygen)

Na = 22.99 g/mol
Cl = 35.45 g/mol
O = 16.00 g/mol

Molar mass of NaClO = 22.99 + 35.45 + (16.00 x 1) = 74.45 g/mol

Moles of NaClO = mass of NaClO / molar mass of NaClO = 8 g / 74.45 g/mol = 0.107 moles

Lastly, we need to convert the 100 mL of solution to liters (since molarity is defined as moles per liter).

Volume of solution = 100 mL / 1000 mL/L = 0.1 L

Now, we can substitute the values into the molarity formula:

Molarity = 0.107 moles / 0.1 liters = 1.07 M

So, the molarity of the bleach solution is 1.07 M (molar).