Two charges repel each other with a force of 10-6N when they are 10cm apart. when they are brought closer together until they are 2cm apart the force between them becomes?

Plz ans this q

To find the force between the charges when they are brought closer together, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Let's assume that the charges are q1 and q2, and the initial distance between them is r1 = 10cm and the initial force is F1 = 10^(-6) N. Let's also assume that the final distance between them is r2 = 2cm.

According to Coulomb's Law, the force between the charges can be calculated using the equation:

F = k * (q1 * q2) / r^2

where F is the force, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the charges, and r is the distance between them.

We can now solve for the force when the charges are brought closer together:

F2 = k * (q1 * q2) / r2^2

In this case, F2 is the force when the charges are 2cm apart.

Using the values given, we can substitute them into the equation:

F2 = (9 x 10^9 Nm^2/C^2) * (q1 * q2) / (2cm)^2

Now, we have all the values we need to calculate the force when the charges are 2cm apart.

To find the force between two charges at different separations, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Let's start by identifying the given values:
- Initial distance (r1) = 10 cm = 0.1 m
- Final distance (r2) = 2 cm = 0.02 m
- Initial force (F1) = 10^-6 N

Now, we can calculate the final force (F2) between the charges. Since the relationship is inversely proportional to the square of the distance, we can use the formula:

F2 = (F1 * (r1^2)) / r2^2

Plugging in the values, we have:

F2 = (10^-6 N * (0.1 m)^2) / (0.02 m)^2

Simplifying this equation step by step:
F2 = (10^-6 N * 0.01 m^2) / 0.0004 m^2
F2 = 10^-8 N / 0.0004 m^2
F2 = 2.5 * 10^-5 N

Therefore, when the charges are brought closer together until they are 2cm apart, the force between them becomes 2.5 * 10^-5 N.

6*10^-5N