A 500 kg go-cart is traveling at 15 m/s when the driver slams on the brakes. The cart comes to a stop in 7 m. If the same braking force is applied, how far will the cart travel after braking if it were traveling at 32 m/s?
average speed during stop = 15/2 = 7.5m/s
time to stop = 7 m / 7.5 m/s = .933 s
a = -15/.933 = -16.1 m/s^2
F = m a = 500(-16.1) = -8036 N
a = same a = -16.1
v = Vi + a t
0 = 32 -16.1 t
t = 32/16.1 = 1.99 s
d = Vi t + (1/2)at^2
= 32(1.99) - 8(4) = 32 m
d = Vi t - (16.1/2)t^2