What are the intercepts for 1.9x-1.9y=3.8
http://www.jiskha.com/display.cgi?id=1393896576
that has the y axis intercept.
for x axis what is x when y = 0?
x = 2
so
the two are
(0, -2)
(2, 0)
Thanks Damon!
You are welcome :)
To find the intercepts of a linear equation, we need to set one of the variables to zero and solve for the other variable. In this case, let's find the x-intercept first by setting y to zero and solving for x.
So, when we set y = 0, the equation becomes:
1.9x - 1.9(0) = 3.8
Simplifying, we have:
1.9x = 3.8
To isolate x, divide both sides of the equation by 1.9:
x = 3.8 / 1.9
x = 2
Therefore, the x-intercept is at (2, 0).
Next, let's find the y-intercept by setting x to zero and solving for y.
When we set x = 0, the equation becomes:
1.9(0) - 1.9y = 3.8
Simplifying, we have:
-1.9y = 3.8
To isolate y, divide both sides of the equation by -1.9:
y = 3.8 / -1.9
y = -2
Therefore, the y-intercept is at (0, -2).
In summary, the intercepts for the equation 1.9x - 1.9y = 3.8 are (2, 0) for the x-intercept and (0, -2) for the y-intercept.