Find vector a<3,2,-4> X vector b<-6, 9,0>
<-36,24,15>
I got ( +36 , 24 , 39 )
My Bad. I used <3,2,4>
Hey Alexis, between the two of us we have been doing an awful lot of problems for you. Many of them are the same old, same old. It is time for you to try and post what you did.
Go back and check your volleyball question. I just saw it and you missed the angle of launch in your equations.
To find the cross product of two vectors, vector a and vector b, we can use the following formula:
a × b = (a2b3 - a3b2) i + (a3b1 - a1b3) j + (a1b2 - a2b1) k
In this case, vector a = <3, 2, -4> and vector b = <-6, 9, 0>. Let's substitute these values into the formula:
a × b = (2 * 0 - -4 * 9) i + (-4 * -6 - 3 * 0) j + (3 * 9 - 2 * -6) k
= (0 + 36) i + (24 + 0) j + (27 + 12) k
= 36i + 24j + 39k
Therefore, the cross product of vector a and vector b is vector c = <36, 24, 39>.