The following molecular equation represents the reaction that occurs when aqueous solutions of lead(II) nitrate and magnesium chloride are combined.
Pb(NO3)2 (aq) + MgCl2 (aq) PbCl2 (s) + Mg(NO3)2 (aq)
Write the balanced net ionic equation for the reaction.
Pb(NO3)2 (aq) + MgCl2 (aq) ----> PbCl2 (s) + Mg(NO3)2 (aq)
Pb++ + 2NO3- + Mg++ + 2Cl- ---> PbCl2 + Mg++ + 2 NO3-
Mg and NO3 the same both sides, ions so
net:
Pb++ + 2 Cl- ---> PbCl2 solid
i have so many boxes to fill in for example one box +one box+one box.
So how will this answer be and let me know if it is aq, l, solid in each box.
thanks
Oh, here comes another chemistry question! Brace yourself for an explosion of laughter!
Alright, let's balance that net ionic equation, shall we?
First, let's break down the equation into its ionic components:
Pb2+ (aq) + 2NO3- (aq) + Mg2+ (aq) + 2Cl- (aq) -> PbCl2 (s) + 2Mg2+ (aq) + 2NO3- (aq)
Now, let's simplify it by removing the spectators (ions that appear on both sides of the equation, doing nothing more than watching the show):
Pb2+ (aq) + 2Cl- (aq) -> PbCl2 (s)
Voila! We've got our balanced net ionic equation, and we didn't even blow anything up (this time)!
To write the net ionic equation, we need to first write the balanced chemical equation.
The given molecular equation is:
Pb(NO3)2 (aq) + MgCl2 (aq) → PbCl2 (s) + Mg(NO3)2 (aq)
Step 1: Write the balanced chemical equation using the correct formulas and coefficients.
Pb(NO3)2 (aq) + 2 MgCl2 (aq) → PbCl2 (s) + 2 Mg(NO3)2 (aq)
Now that we have the balanced chemical equation, we can write the net ionic equation by excluding the spectator ions (ions that appear on both sides of the equation without undergoing a change).
The ionic compounds Pb(NO3)2 and Mg(NO3)2 dissociate into their respective ions when dissolved in water, while PbCl2 and MgCl2 are both solid compounds and do not dissociate.
The net ionic equation can be written by only including the ions that undergo any change:
Pb2+(aq) + 2 Cl-(aq) → PbCl2(s)
Therefore, the balanced net ionic equation for the reaction is:
Pb2+(aq) + 2 Cl-(aq) → PbCl2(s)