Write the net ionic equation for the following molecular equation.
CoI2(aq) + K2CO3(aq) CoCO3(s) + 2KI(aq)
Co^2+(aq) + CO3^2-(aq) ==> CoCO3(s)
To write the net ionic equation, we need to first write the balanced molecular equation.
The balanced molecular equation for the given reaction is:
CoI2(aq) + K2CO3(aq) -> CoCO3(s) + 2KI(aq)
In a net ionic equation, we only include the species that are directly involved in the reaction. Any spectator ions that do not undergo any change are omitted. Spectator ions are present on both sides of the equation and do not participate in the reaction.
Let's now break down the equation into its ionic form. Remember that compounds dissolved in water are broken down into their respective ions.
CoI2(aq) dissociates into:
Co2+ (aq) + 2I- (aq)
K2CO3(aq) dissociates into:
2K+ (aq) + CO3^2- (aq)
CoCO3(s) is a solid and does not dissociate into ions.
2KI(aq) dissociates into:
2K+ (aq) + 2I- (aq)
Now that we have the ions, we can write the net ionic equation by canceling out the spectator ions. In this case, the spectator ions are 2K+ (aq) and 2I- (aq) since they appear on both sides of the equation.
The net ionic equation for the given reaction is:
Co2+ (aq) + CO3^2- (aq) -> CoCO3(s)
Therefore, the net ionic equation for the reaction between CoI2(aq) and K2CO3(aq) is:
Co2+ (aq) + CO3^2- (aq) -> CoCO3 (s)