What is the molarity of a 25.0% (v/v) aqueous isopropyl alcohol solution? the density of isopropyl alcohol ( C3H8O, molar mass 60.1g/mol) is 0.786g/ml
Well, well, well. Looks like we've got a chemistry question here. Hold on tight, because I'm about to spice it up with some clown humor!
To find the molarity of the solution, we'll need to do a little bit of calculation. But don't worry, I promise it won't be as scary as facing a clown with a bucket of confetti.
First, let's determine the density of isopropyl alcohol in g/mL. You've given the density as 0.786 g/mL, which is probably its regular walking speed. That value will come in handy later, so keep it handy like a clown with a squirting flower.
Now, we have a 25.0% (v/v) solution, which means that we have 25.0 mL of isopropyl alcohol for every 100 mL of solution.
To calculate the molarity, we need to convert the volume of the isopropyl alcohol to moles. But before we do that, let's convert the volume to grams using the density. Remember, the density is 0.786 g/mL, so multiply it by the volume of isopropyl alcohol (25.0 mL) to find the mass.
25.0 mL x 0.786 g/mL = 19.65 g
Now that we have the mass, we can calculate the number of moles by dividing the mass by the molar mass of isopropyl alcohol. The molar mass of isopropyl alcohol (C3H8O) is 60.1 g/mol.
19.65 g / 60.1 g/mol = 0.3269 mol
Finally, to find the molarity, we divide the number of moles of isopropyl alcohol by the volume of the solution in liters. Since 25.0 mL is equivalent to 0.025 L, we divide 0.3269 mol by 0.025 L.
0.3269 mol / 0.025 L = 13.076 M
And there you have it, folks! The molarity of the 25.0% (v/v) aqueous isopropyl alcohol solution is approximately 13.076 M. Clown-approved and ready to make some scientific comedy!
To find the molarity of a solution, we need to know the mass of the solute (isopropyl alcohol) and the volume of the solution. Let's calculate it step-by-step.
Step 1: Convert the given percentage to a decimal.
The concentration is given as 25.0% (v/v), which means 25.0 mL of isopropyl alcohol is present in 100 mL of the solution. We need to convert this percentage to a decimal by dividing it by 100:
25.0% = 25.0 / 100 = 0.25
Step 2: Calculate the mass of isopropyl alcohol.
To find the mass, we need to multiply the volume by the density of isopropyl alcohol:
Mass = Volume × Density
Since the density is given as 0.786 g/mL and the volume is 25.0 mL, we have:
Mass = 25.0 mL × 0.786 g/mL = 19.65 g
Step 3: Determine the molar mass of isopropyl alcohol.
The molar mass of isopropyl alcohol (C3H8O) is given as 60.1 g/mol.
Step 4: Calculate the number of moles of isopropyl alcohol.
The number of moles can be calculated using the formula:
Number of moles = Mass / Molar mass
In this case, the mass is 19.65 g and the molar mass is 60.1 g/mol:
Number of moles = 19.65 g / 60.1 g/mol = 0.327 moles
Step 5: Calculate the volume of the solution in liters.
The volume of the solution can be calculated by dividing the mass of isopropyl alcohol by its density:
Volume = Mass / Density
In this case, the mass is 19.65 g and the density is 0.786 g/mL:
Volume = 19.65 g / 0.786 g/mL = 25.0 mL = 0.025 L
Step 6: Calculate the molarity.
Molarity (M) is defined as moles of solute per liter of solution. Since we have 0.327 moles of isopropyl alcohol and the volume of the solution is 0.025 L, we can calculate the molarity as follows:
Molarity = Number of moles / Volume
Molarity = 0.327 moles / 0.025 L = 13.08 M
Therefore, the molarity of the 25.0% (v/v) aqueous isopropyl alcohol solution is approximately 13.08 M.
To find the molarity of a solution, we need to know the moles of the solute (in this case, isopropyl alcohol) and the volume of the solution.
First, let's calculate the moles of isopropyl alcohol. To do this, we'll use the percent by volume (v/v) and the density of isopropyl alcohol.
Given:
Percent by volume (v/v) = 25.0%
Density of isopropyl alcohol = 0.786 g/ml
Molar mass of isopropyl alcohol (C3H8O) = 60.1 g/mol
Step 1: Convert the percent by volume to grams
To do this, assume we have 100 ml of the solution.
25.0% of 100 ml is 25 ml isopropyl alcohol.
Step 2: Calculate the mass of isopropyl alcohol in grams
Mass = Volume x Density
Mass = 25 ml x 0.786 g/ml
Step 3: Calculate the moles of isopropyl alcohol
Moles = Mass / Molar mass
Moles = (25 ml x 0.786 g/ml) / 60.1 g/mol
Now that we have the moles of isopropyl alcohol, we need to determine the volume of the solution to calculate the molarity.
Note: The molarity (M) is defined as moles of solute per liter of solution.
Step 4: Convert ml to liters
Given that 1000 ml = 1 L, we divide the volume by 1000.
Volume = 25 ml / 1000
Step 5: Calculate the molarity
Molarity (M) = Moles / Volume
By following these steps and substituting the values we found, we can calculate the molarity of the 25.0% (v/v) aqueous isopropyl alcohol solution.
25% v/v means 25.0 g isopropyl alcohol in 100 mL solution.
mols C3H8O = grams/molar mass
Convert 100 mL of the solution to grams using density, then M = mols/L soln.