physics

The spring constant of the spring in the
figure is 25 N/m, and the mass of the object
is 4 kg. The spring is unstretched and the
surface is frictionless. A constant 18 N force is
applied horizontally to the object (stretching
the spring).
v0 = 0
Find the speed of the object after it has
moved a distance of 0.35 m.
Answer in units of m/s

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  1. the total energy is W+K=U
    So it would be Fd+(.5*m*v^2)=.5*k*x^2
    Plug in the numbers, 18*.35+.5*25*v^2=.5*25*.35^2
    6.3+12.5*v^2=1.53125
    v=sqrt0.3815 (ignore the negative)
    v=0.61765m/s

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    posted by briana

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