The slope of the tangent line to the graph of a function, h(t) is 7/2t
The function passes through the point (5,3)
Find h(4)
well, we can find an approximation to h(4) by assuming that the tangent line at (5,3) stays close to the curve. So, assuming that you meant the slope is 7/(2t), h'(5) = 7/10
The tangent line is thus
7-3 = 7/10 (x-5)
now, plug in x=4 to approximate h(4)
If you meant h'(t) = (7/2)t, then make the appropriate adjustment