A gas has a volume of V1 = 550 mL. If the
temperature is held constant, what volume
would the gas occupy if P2 = 22 P1?
Answer in units of mL
P V = n R T constant here
so
550 mL/ 22 = 25 mL
To answer this question, we need to use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is held constant.
Boyle's Law formula:
P1 * V1 = P2 * V2
Given:
P2 = 22 * P1
V1 = 550 mL
Let's substitute the given values into the formula and solve for V2:
P1 * V1 = P2 * V2
P1 * 550 mL = (22 * P1) * V2
Now, cancel out the P1 on both sides:
550 mL = 22 * V2
To solve for V2, divide both sides by 22:
V2 = 550 mL / 22
V2 = 25 mL
Therefore, the gas would occupy a volume of 25 mL if P2 = 22 P1.