net ionic equation for the following molecular equation. HNO3 is strong electrolyte and CH3COOH is weak electrolyte. NaCH3COO(aq)+HNO3(aq)----->NaNO3(aq)+CHOOH(aq

CH3COO^- + H^+ ==> CH3COOH

Thank you! i will try that and see if i get it right and let you know of the outcome.

Than you for your help much appreciated..

the same question says use H+ for the hydronium ion, CH3OOH for acetic acid and CH3COO for the acetate ion.

answer + answer---> answer + answer

it has four boxes, pretend the answer is one box. i hope this helps

There is no other "answer" unless you want to include H2O as the other answer. I don't think that's necessary. Since you're using H^+ for H3O^+ that leaves a H2O for the right (but I think all of that is taken care of by the (aq) phases.

so i should have CH3COO^- + H^+ ==> CH3COOH +H2O???

as my online test has four boxes

Also i would be very grateful if u can explain how u got the answer so i know how to work it out in future please.

CH3COONa(aq) + HNO3(aq) ==> NaNO3(aq) + CH3COOH(aq)

If we convert all of that to an ionic equation we have
CH3COO^-(aq) + Na^+ + H3O^+ + NO3^-(aq) ==> Na^+(aq) + NO3^-(aq) + C3COOH(aq)
Na^+(aq) cancels.
NO3^-(aq) cancels. We are left with
CH3COO^-(aq) + + H3O^+(aq) ==> CH3COOH(aq),
Since the problem tells you to use H^+ for H3O^+ then
CH3COO^-(aq) + H^+(aq) ==> CH3COOH(aq) + H2O(l)
That's the only thing I csn think of. Perhaps another tutor will have another thought.

I think my last post shows how I arrive at th final answer. The rules are

1. write the molecular equation.
2. Break the molecules into ions.
a. strong electrolytes become all ions.
b. solids (precipitates and there are none in this equation) are written as (s) for solids) and written as the molecule.
c. weak electrolytes are written as the molecule
d. gases (none in this equation) are written as the molecule.

Step 3 is to cancel ions on the left and right that are the same.

4. What's left is the NET ionic equation.

I got that answer wrong.

You was right I didn't need H2O

how u explained the last post, can u please explain in details like that for this question.

write the net ionic equation for the following molecular equation.

2Crl(aq)+3NaCO3(aq) ---> Cr2(CO3)3(s) + 6NaI(aq)