net ionic equation for the following molecular equation. HNO3 is strong electrolyte and CH3COOH is weak electrolyte. NaCH3COO(aq)+HNO3(aq)----->NaNO3(aq)+CHOOH(aq
To determine the net ionic equation, you first need to write the balanced molecular equation. Then, split the ionic compounds into their respective ions and eliminate the spectator ions to write the net ionic equation.
First, let's write the balanced molecular equation for the given reaction:
NaCH3COO(aq) + HNO3(aq) → NaNO3(aq) + CHOOH(aq)
Now, let's split the ionic compounds into their ions:
NaCH3COO(aq) → Na+(aq) + CH3COO-(aq)
HNO3(aq) → H+(aq) + NO3-(aq)
NaNO3(aq) → Na+(aq) + NO3-(aq)
CHOOH(aq) → C2H3O2-(aq) + H+(aq)
Next, eliminate the spectator ions from both sides of the equation. These are the ions that appear on both sides without undergoing any change:
Na+(aq) and NO3-(aq) appear on both the reactant and product side.
Now, write the net ionic equation by removing the spectator ions:
CH3COO-(aq) + H+(aq) → C2H3O2-(aq)
Therefore, the net ionic equation for the given molecular equation is:
CH3COO-(aq) + H+(aq) → C2H3O2-(aq)