how to calculate the amount of heat in calories absorbed when 50.0 g of water at 20 degrees C spreads over your skin and warms the body temperature, 37 degrees C

To calculate the amount of heat absorbed when water at a lower temperature warms up to body temperature, you can use the equation:

Q = m * C * ΔT

Where:
Q: Amount of heat absorbed (in calories)
m: Mass of the substance (in grams)
C: Specific heat capacity of the substance (in calories/gram°C)
ΔT: Change in temperature (in °C)

In this case, the mass of water (m) is 50.0 g, the specific heat capacity of water (C) is 1 cal/g°C, and the change in temperature (ΔT) is from 20°C to 37°C.

Substituting these values into the equation:

Q = 50.0 g * 1 cal/g°C * (37°C - 20°C)

Simplifying the equation:

Q = 50.0 g * 1 cal/g°C * 17°C

Q = 850 cal

Therefore, the amount of heat absorbed when 50.0 g of water at 20°C spreads over your skin and warms to body temperature (37°C) is 850 calories.

q = mass H2O x specific heat H2O x (Tfinal-Tinitial)