Write a balanced equation for the complete combustion of 1 mole of ethyne gas (C2H2) ?
C2H2 + (5/2)O2 ==> 2CO2 + H2O
Chemistry notes
The balanced equation for the complete combustion of 1 mole of ethyne gas (C2H2) is:
C2H2 + 5/2 O2 -> 2CO2 + H2O
To write a balanced equation for the complete combustion of ethyne gas (C2H2), follow these steps:
Step 1: Determine the reactants and products.
In this case, the reactant is ethyne gas (C2H2). The product of complete combustion is carbon dioxide (CO2) and water (H2O).
Step 2: Write out the unbalanced equation.
C2H2 + O2 → CO2 + H2O
Step 3: Balance the carbon atoms.
The number of carbon atoms is already balanced. There are 2 carbon atoms on each side of the equation.
C2H2 + O2 → 2CO2 + H2O
Step 4: Balance the hydrogen atoms.
There are 2 hydrogen atoms on the left side and 2 hydrogen atoms in the water on the right side. The equation is already balanced.
C2H2 + O2 → 2CO2 + 2H2O
Step 5: Balance the oxygen atoms.
On the left side, we have 2 oxygen atoms from the O2 molecule, and on the right side, we have 4 oxygen atoms in the CO2 molecules and 2 oxygen atoms in the H2O molecules. To balance the oxygen, we need to add a coefficient in front of O2:
C2H2 + 5/2 O2 → 2CO2 + 2H2O
Step 6: Simplify the coefficients.
Multiply all the coefficients by 2 to eliminate fractions:
2C2H2 + 5O2 → 4CO2 + 4H2O
Therefore, the balanced equation for the complete combustion of 1 mole of ethyne gas (C2H2) is:
2C2H2 + 5O2 → 4CO2 + 4H2O