The equation of line AB is (y-3) = 5 (x - 4). What is the slope of a line perpendicular to line AB?
y - 3 = 5 x -20
y = 5 x - 17
slope m = 5
slope of perpendicular = -1/m = -1/5
y - 3 = 5 x -20
y = 5 x - 17
slope m = 5
slope of perpendicular = -1/m = -1/5
To find the slope of a line perpendicular to line AB, we need to know the slope of line AB.
Looking at the equation of line AB, (y-3) = 5(x-4), we can see that the equation is in the form of y - y1 = m(x - x1), where the point (x1, y1) lies on the line, and m is the slope of the line.
Comparing this with the given equation, we can identify that the point (x1, y1) is (4, 3), and the slope, m, is 5.
Now, a line perpendicular to line AB will have a slope that is the negative reciprocal of the slope of line AB. In other words, if the slope of line AB is m, the slope of the perpendicular line will be -1/m.
So, the slope of a line perpendicular to line AB is -1/5.