For a given two-digit number, the second digit is 2 more than 5 times the first digit. Also, 5 times the first digit is 3 more than the second digit. Find the two-digit number,
10s digit
U=5t+2
5t=u+3
5t=5t+5
t=t+1
0=1
No solution
To find the two-digit number, let's break down the information given into equations. Let's denote the first digit as "x" and the second digit as "y."
According to the first condition, the second digit is 2 more than 5 times the first digit:
y = 5x + 2
According to the second condition, 5 times the first digit is 3 more than the second digit:
5x = y + 3
Now we have a system of two equations with two unknowns. We can solve this system to find the values of x and y.
Substituting the first equation into the second equation, we have:
5x = (5x + 2) + 3
Simplifying the equation:
5x = 5x + 5
0 = 5
Wait a minute! The equation is inconsistent and doesn't make sense. The system of equations given does not have a solution. It's possible that there is an error or contradiction in the information provided.
If the first digit is t (for tens) and the 2nd digit is u (for units), then
u = 5t+2
5t = u+3
Sorry, no solution.
Care to rethink it?