Suppose that 6.68 kg of shaved ice is needed to keep medications cold in a room that has no refridgerator. What amount of heat (in calories) is needed to be removed from water at 0 degrees Celsius to make ice. Write your answer correct to two decimal places.
Q=mλ=6.68•335000=2.24•10⁶ J
To find the amount of heat needed to remove from water at 0 degrees Celsius to make ice, we can use the specific heat capacity of water and the heat of fusion of water.
The specific heat capacity of water is 1 calorie/gram °C, which means it takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius.
The heat of fusion of water is the amount of heat needed to convert 1 gram of water at 0 degrees Celsius to 1 gram of ice at 0 degrees Celsius. The heat of fusion of water is 79.7 calories/gram.
Given that 6.68 kg (or 6680 grams) of shaved ice is needed, we can calculate the amount of heat needed to remove from water at 0 degrees Celsius to make ice.
Amount of heat = (mass of ice) x (heat of fusion of water)
= (6680 grams) x (79.7 calories/gram)
= 531,596 calories
Therefore, the amount of heat needed to be removed from water at 0 degrees Celsius to make ice is 531,596 calories.