The element P (mass no.=39) and Q (mass no. =80) contain 20 and 45 neutrons respectively in their nucleus. Give their electron configuration separately
Element P electron configuration is
2-8-8-1
Element Q electron configuration is
2-8-18-7
Electron configuration of element P is
1s2, 2s2, 2p6, 3s2,3p6,4s1
Electron configuration of element Q is
1s2,2s2,2p6,3s2,3p6,4s2,3d10,4p5
An atom has the electron configuration of [Ar] 4s2 3d10*4p5 if its mass no is 80,what will its no of protons and neutronsbe?
To determine the electron configuration of elements P and Q, we need to first identify their atomic numbers. The atomic number represents the number of protons present in an atom and is equal to the number of electrons.
For element P, we're given that it has 20 neutrons. To find the atomic number, we can subtract the number of neutrons from the mass number (which is given as 39).
Atomic number of P = Mass number - Number of neutrons = 39 - 20 = 19
Now that we know the atomic number of P is 19, we can proceed to determine its electron configuration. One way to find the electron configuration is by using the periodic table.
The atomic number of 19 indicates that P is potassium (K) as seen on the periodic table. To determine the electron configuration of potassium, we follow the Aufbau principle, which states that electrons fill the lowest energy levels first.
The electron configuration of potassium (K) is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^1
Now let's move on to element Q. We're given that it contains 45 neutrons and its mass number is 80. We can apply the same process to find its atomic number.
Atomic number of Q = Mass number - Number of neutrons = 80 - 45 = 35
The atomic number 35 corresponds to the element bromine (Br) on the periodic table. Therefore, Q is bromine.
The electron configuration of bromine (Br) is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^5
So, the electron configurations for element P and Q (potassium and bromine, respectively) are:
P: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1
Q: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^5