Fine the distance between points P(5, -4) and Q(1, -2)

I come up with d= 7.211 but im not sure if its right.

distance

= √( (5-1)^2 + (-4+2)^2 )
= √(16 + 4)
= √20
= appr 4.47

I would leave it in exact form of √20 or 2√5

Thank you so much!

welcome

To find the distance between two points on a coordinate plane, you can use the distance formula, which is derived from the Pythagorean theorem.

The distance formula is:
d = √((x2 - x1)^2 + (y2 - y1)^2)

Let's calculate the distance between points P(5, -4) and Q(1, -2).

Using the distance formula:
d = √((1 - 5)^2 + (-2 - (-4))^2)
= √((-4)^2 + (2)^2)
= √(16 + 4)
= √20
= 4.472

Therefore, the distance between points P(5, -4) and Q(1, -2) is approximately 4.472 units.