Two poles are 20 feet tall and 30 feet tall, respectively. If they are 30 feet apart, how far is it

from the top of one pole to the top of the other pole? Round your answer to the nearest
tenth of a foot.

up ten and over thirty

sqrt (100+900)

10 sqrt 10

31.6

i'm not sure what you mean by up 10 and over thirty?

You went over from the top of the twenty foot pole to top of the thirty foot pole horizontally. That was thirty feet horizontal. Then you go up ten to go up from 20 to 30

Nevermind, I understand!

To find the distance from the top of one pole to the top of the other pole, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the distance between the two poles forms the base of a right triangle, and the heights of the poles form the legs of the right triangle. Let's label the shorter pole as pole A (20 feet tall) and the taller pole as pole B (30 feet tall). We will also label the distance between the poles as d (30 feet).

Using the Pythagorean theorem, we have:
d^2 = A^2 + B^2

Substituting the given values:
d^2 = 20^2 + 30^2
d^2 = 400 + 900
d^2 = 1300

To find the distance d, we take the square root of both sides:
d ≈ √1300
d ≈ 36.06 feet

Therefore, the distance from the top of one pole to the top of the other pole is approximately 36.1 feet when rounded to the nearest tenth of a foot.