Find the slope of the tangent line to the graph y = x-3 at the point (0.5, 8).

Answer

-48

-12

4

16

Now wait a minute. Try this one yourself first.

not exactly sure how to solve it...... do i use the tangent line equation f(c+change in x)................???

Exactly the same way I did the ellipse.

find dy/dx, the slope

call it m at the given point
use the point in the equation to find b in y = m x + b

k thanks soooo much!!!

To find the slope of the tangent line to the graph, we can use the derivative of the function y = x - 3. The derivative represents the rate of change of the function at any given point.

The derivative of y = x - 3 is simply 1, as the derivative of any constant or linear term is always 0. Therefore, the slope of the tangent line to the graph is 1.

To verify this, we can substitute the x-value (0.5) into the derivative to find the rate of change at that point.

So, at x = 0.5, the rate of change is 1.

Therefore, the slope of the tangent line to the graph at the point (0.5, 8) is 1.

None of the given answer choices (-48, -12, 4, 16) match with the calculated slope, which is 1.