A rectangle is 3times as long as it is wide the perimeter is 60cm. Find the dimensions of the rectangle round to nearest tenth if necessary answers are 7.5cm.by22.5cm., 7.5cm.by52.5cm., 20cm.by60cm., 15cm.by22.5cm thanks
To solve this problem, let's assume the width of the rectangle is "x" cm.
According to the given information, the length of the rectangle is 3 times the width. So, the length would be 3x cm.
The perimeter of a rectangle is calculated by adding the lengths of all its sides. In this case, it is given as 60 cm.
Therefore, the perimeter of the rectangle can be represented as:
2(width) + 2(length) = 60 cm
Substituting the values, we get:
2(x) + 2(3x) = 60 cm
Simplifying the equation:
2x + 6x = 60 cm
8x = 60 cm
x = 60 cm / 8
x ≈ 7.5 cm
So, the width of the rectangle is approximately 7.5 cm. The length can be found by multiplying the width by 3:
Length = 3(x) ≈ 3(7.5 cm) ≈ 22.5 cm
Therefore, the dimensions of the rectangle are approximately 7.5 cm by 22.5 cm.
To find the dimensions of the rectangle, we can use the given information. Let's denote the width of the rectangle as "w", and since the length is 3 times the width, the length would be "3w".
The perimeter of a rectangle is calculated by adding up all the sides, so the formula for the perimeter is:
Perimeter = 2(Length + Width)
Substituting the values we have, we get:
60 = 2(3w + w)
Simplifying further:
60 = 2(4w)
Divide both sides by 2:
30 = 4w
Now divide both sides by 4:
7.5 = w
So the width of the rectangle is 7.5 cm.
To find the length, we already know it's 3 times the width, so:
Length = 3w
Length = 3(7.5)
Length = 22.5 cm
Therefore, the dimensions of the rectangle are 7.5 cm by 22.5 cm.
P = 2L + 2W
60 = 2(3W) + 2W
60 = 6W + 2W
60 = 8W
7.5 = W